Arthur D. answered 07/23/14
Tutor
5.0
(255)
Mathematics Tutor With a Master's Degree In Mathematics
let x= # of new trees
(20+x)(116-4x)
2320+116x-80x-4x2
2320+36x-4x2
use -b/2a for the equation in the form ax2+bx+c, or -4x2+36x+2320
-36/(2)(-4)=-36/-8=4.5 trees but you can't have half of a tree so you use 4 or 5
20 trees produces 20*116=2320 bushels
21 trees produces 21*112=2352 bushels
22 trees produces 22*108=2376 bushels
23 trees produces 23*104=2392 bushels
24 trees produces 24*100=2400 bushels
25 trees produces 25*96=2400 bushels
26 trees produces 26*92=2392 bushels
notice that 24.5*98=2401 bushels, the maximum, but you can't have half of a tree
plant 4 or 5 trees for a total yield of 2400 bushels
Arthur D.
07/23/14