
Andy C. answered 08/23/17
Tutor
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Math/Physics Tutor
lala = oola(14)
loal = oola(12)
ola = oola(10)
Rewriting the equations:
a^2*l^2 = 14*a*l*o^2
a*l^2*o = 12*a*l*o^2
a*l*o = 10 * a*l*o^2
Cancelling:
a*l = 14*o^2 <--- divides by a*l
l = 12*o <---- divides by a*l*o
1 = 10 * o <--- divides by a*l*o
So o = 1/10
Plugging into second equation:
l = 12 (1/10) = 12/10 = 5/6
Plugging into first equation:
a*(5/6) = 14*(1/10)^2 = 14/100 = 7/50
a = 7/50*6/5 = 42/250 = 21/125 =(3*7)/ (5*5*5) <--- reduced to lowest terms
Next rs = oola = o^2*l*a = (1/10)^2*(5/6)*(21/125) = 105/(600*125) = 21/(600*25) = 7/(200*25) = 7/5000
Now we check the original equations:
lala = l^2*a^2 = (5/6)^2*(21/125)^2 = (5*5*21*21)/(6*6*125*125) = (7*7)/(2*2*25*25) = 49/2500
14rs = 14(7/5000) = (7*7)/2500 = 49/2500. So lala = 14rs.
ola = (1/10)(5/6)(21/125) = (5*21)/(10*6*125) = 7/(2*2*125) = 7/500
10rs = 10(7/5000) = 7/500. So ola = 10rs.
loal = oola(12)
ola = oola(10)
Rewriting the equations:
a^2*l^2 = 14*a*l*o^2
a*l^2*o = 12*a*l*o^2
a*l*o = 10 * a*l*o^2
Cancelling:
a*l = 14*o^2 <--- divides by a*l
l = 12*o <---- divides by a*l*o
1 = 10 * o <--- divides by a*l*o
So o = 1/10
Plugging into second equation:
l = 12 (1/10) = 12/10 = 5/6
Plugging into first equation:
a*(5/6) = 14*(1/10)^2 = 14/100 = 7/50
a = 7/50*6/5 = 42/250 = 21/125 =(3*7)/ (5*5*5) <--- reduced to lowest terms
Next rs = oola = o^2*l*a = (1/10)^2*(5/6)*(21/125) = 105/(600*125) = 21/(600*25) = 7/(200*25) = 7/5000
Now we check the original equations:
lala = l^2*a^2 = (5/6)^2*(21/125)^2 = (5*5*21*21)/(6*6*125*125) = (7*7)/(2*2*25*25) = 49/2500
14rs = 14(7/5000) = (7*7)/2500 = 49/2500. So lala = 14rs.
ola = (1/10)(5/6)(21/125) = (5*21)/(10*6*125) = 7/(2*2*125) = 7/500
10rs = 10(7/5000) = 7/500. So ola = 10rs.