
Andy C. answered 07/10/17
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Let x represent the 30th percentile speed for Normal X with parameters mean=158.9, stdev=6.7
P(X<z) = 0.3 <-- 30th percentile
z = -0.525 <--- from the normal table , doing a reverse lookup
However, this value is the z-score. To convert it back to scale,
-0.525 = (x - 158.9)/6.7
X = 155.3285
-0.525 = (x - 158.9)/6.7
X = 155.3285