This is a question from pre algebra, factoring by grouping.

2m^{2}(m+4) + 5(m+4) - original expression

Hi Summer... I'm not sure what you need as an end result, but here are two possibilities:

2m^{3} + 8m^{2} + 5m + 20 - do the multiplications

(m+4) (2m^{2} + 5) - pull out the common term, (m+4). (2M^{2} + 5) won't factor further.