
Will B. answered 03/30/17
Tutor
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(5)
Experienced & Knowledgeable Math Tutor - UGA Grad
So lets break this apart using the properties of the square root.
3√(-27y7x5z6) = 3(√-27)(√y7)(√x5)(√z6)
√-27 = √(9)(-3) = 3√-3
√y7 = √(y6)(y) = (y3)(√y)
√x5 = √(x4)(x) = (x2)(√x)
√z6 = z3
Simplifying it all we get 3(3√-3)(y3)(√y)(x2)(√x)(z3) = 9y3x2z3√(-3xy)
Hope this helps!