d to the 6th minus h to the third

Question

dfsfaf sg sgasdgas

Answer 1

(a^3 - b^3) = (a - b)(a^2 + ab + b^2)

Multiply right side out to verify.

 

 

d^6 - h^3 = (d^2)^3 - h^3

 

= (d^2 - h)((d^2)^2 + (d^2)*h + h^2)

 

= (d^2 - h)((d^4 + (d^2)*h + h^2)

Answer 2

Hi John;

d⁶-h³

There is nothing more I can do with this.