-(2n-1)+3(n+2)=7

Question

how do I solve this

 

Answer 1

Hi Brenda;

-(2n-1)+3(n+2)=7

First, let's distribute the -1 which is the coefficient to the first parenthetical equation...

-(2n-1)

-1(2n-1)

(-1)(2n)=-2n

(-1)(-1)=1, a negative number multiplied by a negative number is positive.

-2n+1

-2n+1+3(n+2)=7

Second, let's distribute the 3 which is the coefficient in the second parenthetical equation...

3(n+2)

(3)(n)=3n

(3)(2)=6

3n+6

-2n+1+3n+6=7

Let's combine like terms...

-2n+3n=1n=n

1+6=7

n+7=7

n=0

Let's check our work...

-(2n-1)+3(n+2)=7

-[(2)(0)-1]+[3(0+2)]=7

-(0-1)+[(3)(2)]=7

-(-1)+6=7

1+6=7

7=7