Pia R.

asked • 08/26/16# find equation of line through the point (1,-1,1) perpendicular to the line 3x=2y=z and parallel to plane x+y-z=0

## 1 Expert Answer

Kendra F. answered • 08/26/16

Patient & Knowledgeable Math & Science Tutor

**point (1,-1,1)**perpendicular to the

**line 3x=2y=z**and parallel to

**plane x+y-z=0**

v = <1, 1, -1> x <2, 3, 6> = <9, -8, 1>

_{0}, y

_{0}, z

_{0}).

_{0}+ at

_{0}+ bt

_{0}+ ct

Pia R.

08/27/16

Kendra F.

There is only one independent variable on a line. Once you pick one of the coordinate, like z = 6, then x and y must be 2 and 3 respectively. 3(2) = 2(3) = 6

08/27/16

Pia R.

08/27/16

Kendra F.

08/27/16

Pia R.

08/31/16

Pia R.

08/31/16

Kendra F.

**use the point, (1,-1,1) as (x**

_{0}, y_{0}, z_{0}).08/31/16

Kendra F.

**use the given point, (1,-1,1) as (x**

_{0}, y_{0}, z_{0}) so that it is included in the line as well.. at t = 0, (1, -1, 1).08/31/16

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08/26/16