John R. answered 05/01/16
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If you solve by factoring we have
2(x^2+3x-4)=0
2(x+4)(x-1=0
(x+4)= 0 x=-4
x-1=0 x=1
John R.
That is what I solved for.
The zeros are x= -4 and x=1 (where graph crosses or touches the x axis)
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