Andrew M. answered • 03/15/16

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

2/3 - (3x+2)/(3x-3)

= 2/3 - (3x+2)/3(x-1)

The first denominator is 3

The 2nd denominator is 3(x-1)

The LCD ... smallest thing that both 3 and 3(x-1)

divide into... is 3(x-1).

Multiply 2/3 by (x-1)/(x-1)

2(x-1)/3(x-1) - (3x+2)/3(x-1)

= (2x-2 - 3x -2)/3(x-1)

= (-x-4)/3(x-1)