what is the density and the specific gravity of 50 grams in 49 mL

Question

I have 5 questions.

 

what is the density and the specific gravity of the following....

 

1. 50 grams in 49 mL

2. 85 grams in 68 mL

3. 20 grams in 30 mL

4. 15 grams in 60 mL

5. 6 grams in 3 cm³

Answer 1

Hi Karlee,

 

To find the specific gravity of a substance, you will need a fluid to submerge the substance in, if we take water as a standard, the density of water is ρ_water = 1.00g/cm³

(1) M = 50g in V = 49 mL,  1 mL = 1 cm³,   ρ is the density

ρ=M/V = 50 g/ 49 cm³ = 1.02 g/cm³

Specific density =  ρ/ρ_water = 1.02g/cm³/1g/cm³ = 1.02 (sinks)

 

(2) M = 85g in V = 68 mL, 1 mL = 1 cm³, ρ is the density
ρ=M/V = 85 g/ 68 cm³ = 1.25g/cm³
Specific density = ρ/ρwater = 1.25g/cm³/1g/cm³ = 1.25 (sinks)

 

(3) M = 20g in V = 30 mL, 1 mL = 1 cm³, ρ is the density
ρ=M/V = 20g/ 30 cm³ = 0.667g/cm³
Specific density = ρ/ρwater = 0.667/cm³/1g/cm³ = 0.667 (floats)

 

(4) M = 15g in V = 60 mL, 1 mL = 1 cm³, ρ is the density
ρ=M/V = 15g/ 60cm³ = 0.25 g/cm³
Specific density = ρ/ρwater = 0.25 g/cm3/1g/cm3 = 0.25 (floats) 

 

(5) M = 6g in V = 3 cm³, ρ is the density
ρ=M/V = 6g/3 cm³ = 2.00 g/cm³
Specific density = ρ/ρwater = 2.00 g/cm³/1g/cm³ = 2.00 (sinks)