Write the equation of a straight line which has a slope of m = 2/3 and crosses the y -axis at (0, -1/3).

Question

i don't even understand how this question at all.

Answer 1

The question asks you to find the equation in form of y=mx+b

 

They have given you m=2/3 -> y=(2/3)x+b

 

The line crosses the y-axis at (0, -1/3) -> y-intercept

 

Plug the point back in the equation

 

y=(2/3)x+b

 

(-1/3)=(2/3)(0)+b

 

-1/3=b

 

Equation of the line y=(2/3)x-(1/3)