A fair die is thrown 9 times. What is the probability of getting point 1 on exactly 3 of the 9 throws?

Question

A fair die is thrown 9 times. What is the probability of getting point 1 on exactly 3 of the 9 throws? Give your answer as a decimal number, with 4 decimal places.

 

Bernoulli Trials

Answer 1

The probability of getting any point by throwing a fair die is =1/6

Such probability for 9 throws is =(1/6)*(1/6)*(1/6)*(1/6)*(1/6)*(1/6)*(1/6)*(1/6)*(1/6)=(1/6)⁹ 

If we must get 1 on exactly 3 of 9 throws=(1/6)*(1/6)*(1/6)*(3/9)=(1/216)*(1/3)=1/648≈0.0015