One man is three times as old as another. Fifteen years ago the first was six times as old as the second. Find their ages now.

Question

I need help asap

Answer 1

Srijan,

 

Let's call the age of the first man, F; and the age of the second man, S.

 

"One man is three times as old as another":    F=3S

 

"Fifteen years ago the first was six times as old as the second":   F-15=6(S-15)

 

"Find their ages now":  We need to solve the above two simultaneous equations which encapsulate the

information given in the question.

 

Substitute 3S for F in the second equation:

 

3S-15=6(S-15)

75=3S

S=25  and F=3S=75

 

So the age of the first man is 75 years and the second is 25 years.

 

Check: 75-3*25 yes 60=6*10 yes