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limx-0=13cscx^2-13cot^2

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1 Answer

lim{x->0} 13csc(x^2) - 13cot(x^2)

= lim{x->0}13(csc(x^2) - cot(x^2))

= lim{x->0}13((1-cos(x^2))/(sin(x^2)), 0/0

= lim{x->0}13sin(x^2)(2x)/(cos(x^2) 2x), after using L'Hopital's rule

= lim{x->0}13tan(x^2)

= 0

 

Comments

To the guy who thumped down my response:

Could you tell me which part in my approach was wrong? Don't abuse your power of voting.