
Hannah H. answered 04/10/21
Previous University Finance Tutor
Let the inkjet printer be X (costing $107)
Let the LCD monitor be Y (costing $130)
Let the memory chips be Z (costing $90)
We know the there were only 48 pieces of hardware purchased, so we can state the following
X + Y + Z = 48
We also know the total amount of money spent on new hardware came to $4993, so that
107X + 130Y +90Z = 4993
Since they purchased two times as many memory chips as they did LCD monitors, we can substitute 2Y for the variable Z. Resulting in
X + Y + 2Y = 48 or X+ 3Y = 48 and
107X + 130Y + 90(2Y) = 4993 Distribute the parenthesis to get
107X +130Y + 180Y = 4993 or 107X + 310Y = 4993
Now we have two variables (X&Y) so it's easier to solve. The equations are
X+ 3Y = 48
107X + 310Y = 4993
You can use either the substitution method or the elimination method to solve. I find the elimination method to be easiest. Multiply one of the equations so that one of the variables cancels out. If we multiply the first equation by -107, it will cancel out the X variable.
[X+ 3Y = 48] x (-107) which results in -107X - 321Y = -5,136
-107X -321Y = -5,136 then add the equations together and you are left with
+ 107X + 310Y = 4993
0 -11Y = -143 then divide both sides by -11 and the Y variable is 13.
So they bought 13 LCD monitor's, 26 memory chips (twice as many as the LCD Monitors), and 9 Inkjet Printers (48 - 13 - 26 = 9).