Decimal Binary in c

Question

Between 0 and 255 a number will be decided randomly by computer. Then asks to user 3 times a random digit of binary value of the that number. If user enters wrong number for a digit program will select another random number and ask random times random digit.

Answer 1

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#define YES (1)

#define NO (0)

Decimal2Binary(int x, char *bitStr)

{

memset(bitStr,'0',8);

bitStr[8]=0; //null terminates

bitStr[0]=x/128+'0';

x%=128;

bitStr[1]=x/64+'0';

x%=64;

bitStr[2]=x/32+'0';

x%=32;

bitStr[3]=x/16+'0';

x%=16;

bitStr[4]=x/8+'0';

x%=8;

bitStr[5]=x/4+'0';

x%=4;

bitStr[6]=x/2+'0';

x%=2;

bitStr[7]=x+'0';

}

int DoItAgainQuestion()

{

int response=-1;

while ((response<0) || (response>1))

{

printf("Another problem ??? 1=YES 0=NO :>");

scanf("%d",&response);

}

return(response);

}

Go()

{

char bitStr[9];

char inbuff[9];

srand(NULL);

int response=YES;

int iLoop=0;

while (response==YES)

{

int randomIntNum = rand()%255;

Decimal2Binary(randomIntNum,bitStr);

for (iLoop=0; iLoop<3; iLoop++)

{

printf("the random number is %d = ",randomIntNum);

printf(" binary >%s< \n",bitStr); //<---- comment this out !!!

printf("Please input the binary :>");

scanf("%s",inbuff);

if (strcmp(inbuff,bitStr)==0)

{

printf("Yes that is correct...\n");

break;

}

else

{

printf(" sorry that is incorrect - try again ! \n\n");

}

}//for loop

response = DoItAgainQuestion();

} //while

}

main()

{

Go();

}