Anthony T. answered 01/08/21
Patient Science Tutor
Ca (s) + F2 (g) ---> CaF2 (s) ΔG0f = -1167 kj/mole
CaF2 (s) ---->Ca2+(aq) + 2F1- (aq) ΔG0 = -RT LnK = - 8.314 J/mole x 298 K x Ln(3.9 x 0-11) = 59.4 kJ/mole
Add the 2 reactions (CaF2 (s) cancels.) Net reaction is
Ca (s) + F2 (g) -----> Ca2+(aq) + 2F1- (aq) ΔG0f = -1167 kj/mole + 59.4 kj/mole = -1108 kj/mole