Consider the following code What does g(1, 3) evaluate to?

Question

int g (int x, int n) {

for (int i = 0; i < n; i++) {

if (i % 2 == 0) {

x *= i + 1;

continue;

}

x--;

if (x == 0) {

break;

}

}

return x;

}

Answer 1

Entering function g with x=1 and n=3

Statement Values

Entering function g x=1 ; n=3

Entering for loop x=1; n=3; i=0

inside for loop i mod 2 = 0 mod 2 = 0, so x = x*1 = x = 1

continue i=1;

if condition 1 mod 2 = 1, so condition fails

x-- x=x-1 = 1-1 = 0

if (x==0) 0==0 so the conidition it true;

breaks out of the for loop

returns 0

----------------------------------------------------------

using namespace std;

#include <iostream>

int g (int x, int n)

{

for (int i = 0; i < n; i++)

{

if (i % 2 == 0)

{

x *= i + 1;

continue;

}

x--;

if (x == 0)

{

break;

}

}

return x;

}

int main()

{

cout << g(1,3);

}