
Mark M. answered 02/04/15
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Mathematics Teacher - NCLB Highly Qualified
A = p(1 + r/n)nt + d[((1 + r/n)nt - 1) / r], Where A = amount, p = principal, r = rate, n = number of calculations per year, d = amount of deposit, t = time in years.
A = 1900(1 + 0.0035)12·40 +200[((1 + 0.0035)12·40 - 1)) / 0.0425]