
Lauren H. answered 10/23/18
Experienced High School Chemistry Teacher
d + q = 300, d = 300 - q
(.10)d + (.25)q = 43.50
Substitute:
(.10)(300 - q) + .25q = 43.50
30 - .10q + .25q = 43.50
.15q = 13.50
q = 90
d = 210
April V.
asked 10/22/18Samantha has a total of 300 coins, which consists of dimes and quarters. If the collection is worth $43.50, how many of each does she have?
Lauren H. answered 10/23/18
Experienced High School Chemistry Teacher
d + q = 300, d = 300 - q
(.10)d + (.25)q = 43.50
Substitute:
(.10)(300 - q) + .25q = 43.50
30 - .10q + .25q = 43.50
.15q = 13.50
q = 90
d = 210
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