The formula for the Area of a circle is ∏r2.
Let's call the Area of the original circle A.
If ∏r2 is the Area of the original circle, then you need to show the new radius for the smaller circle as r - 6, becuase it decreased by 6.
The formula for the area of the new circle will be ∏(r-6)2 which will be 9 times smaller than ∏r2 or
∏r2 = 9 * ∏(r-6)2
Next divide both sides of the equation by pi to cancel it out, ad you are left with r2 = 9 * (r-6)2
Next take the square root of both sides of the equation:
√(r2 ) = √[9 (r-6)2]
and you get √(r*r ) = √[3*3(r-6)(r-6)]
which is r = 3(r-6)
Next divide both sides of the eqauation by 3 to get
r / 3 = r - 6, so you know that one-third of r is the same as when you take 6 away from r.
Your job then is to figure out what r is that when you divide it by 3 you get the same answer as when you subtract 6 from it, and then plug the answer back into the 2 original equations to make sure that ∏r2 truely is 9 times greater than ∏(r-6)2.
r / 3 = r - 6, so you know that one-third of r is the same as when you take 6 away from r.
Your job then is to figure out what r is that when you divide it by 3 you get the same answer as when you subtract 6 from it, and then plug the answer back into the 2 original equations to make sure that ∏r2 truely is 9 times greater than ∏(r-6)2.
Byron S.
10/08/14