2 V2O5(s) + 5 Si(l) → 4 V(l) + 5 SiO2(s) Given the above balanced equation, calculate the number of grams of silicon required to prepare 359 grams of van

Question

2 V2O5(s) + 5 Si(l) → 4 V(l) + 5 SiO2(s)

Given the above balanced equation, calculate the number of grams of silicon required to prepare 359 grams of vanadium metal.

Your answer should have 3 sig figs.

Answer 1

2 V2O5(s) + 5 Si(l) → 4 V(l) + 5 SiO2(s)

359 g V x (1 mole V/50.9415 g V)  x (5 Si/4 V)  x  (28.0855 g Si/1 mole Si) = 247 g Si

 

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