J.R. S. answered 11/27/17
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
It will be 1/5 of the original molality. Recall that molality (m) is moles of solute/kg solvent. 1 m glucose represents 1 mole of glucose in 1 kg of solvent, so diluting it to 5 kg of solvent does not change the moles of glucose. And since m is not based on final volume of solution, but rather just on kg of solvent, you now have 1 mole glucose in 5 kg solvent, which is 1/5 = 0.2 molal.