
Aaron N. answered 08/05/18
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X = distance to school
(2/3 - 1/5)X = (7/15)X = distance from 7:30 point to 7:45 point
Speed = 4*(7/15)X units/hour
Distance remaining to school at time 7:45 is (1/3)X
Time to cover the remaining distance = distance/speed = (1/3)X / (28/15)X = 5/28 hours = 10.71 minutes
Time of arrival at school = 7:55:42seconds am