how many milliliters of 0.05M HCl is required to neutralize 1.0g of NaOH?

Question

how many milliliters of 0.05M HCl is required to neutralize 1.0g of NaOH?

Answer 1

Look at the balanced equation for the reaction in question:

HCl + NaOH ===> NaCl + H₂O

1 mole of HCl will be required for each 1 mole of NaOH

How many moles of NaOH are present?

-- 1.0 g NaOH x 1 mole NaOH/40 g = 0.025 moles NaOH present.

This will require 0.025 moles of HCl for complete neutralization.  How many mls will that be?

-- 0.05 moles HCl/L (x L) = 0.025 moles.  x = 0.5 liters = 500 mls