Algebra 1, Math

Question

Two men start walking at the same time. One man walks at a rate of 4 kilometers per hour, and the other walks at a rate of 3 kilometers per hour. The first man arrives at the destination 3 hours before the second man. What is the distance that each man walked?

Answer 1

The first man walks at the rate of 4km/hr and 2nd man walks at the rate of 3km/hr.

Let total distance be x km

1st man covers 4km in 1 hr

1st man covers 1km in 1/4 hr

1st man covers xkm in x/4 hr

Similarly,

2nd man covers 3km in 1 hr

2nd man covers 1km in 1/3 hr
2nd man covers xkm in x/3 hr

Since, 1st man reached destination 3 hours earlier

x/3-3 = x/4

x/3-x/4 = 3

x/12 = 3

x = 36 km

Hence they covered 36 km

Proof:

1st man covers 4km in 1 hr
1st man covers 1km in 1/4 hr
1st man covers 36km in 36/4 = 9 hr
Similarly,
2nd man covers 3km in 1 hr
2nd man covers 1km in 1/3 hr
2nd man covers 36km in 36/3 = 12 hr

Time difference between two person = 3 hours

1st person reached the destination 3 hours before 2nd person

 

 

Answer 2

d = r · t

4t = 3(t +3)

 

Can you solve for t and answer?