Michael J. answered • 06/17/17

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Let # of spoons = x

Let # of forks = y

Let # of knives = z

Then we have the equation

x + y + z = 40 eq1

3x + 3.6y + 3.9z = 140 eq2

This is one solution.

If we change the variables so that spoons is y, forks is z, and knives is y. We can alter the second equation to get a second solution.

spoons = x , y , z

forks = y , z , x

knives = z , x , y

Given this arrangement, you will have a maximum of 3 solutions.

Mark M.

06/17/17