
Andrew M. answered 06/06/18
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
n = Nancy's current age
d = Datta's current age
Nancy is twice as many years old as Datta:
n = 2d
three years ago,she was three times older than Datta:
n-3 = 3(d-3)
Since we know n=2d, substitute that into 2nd equation and solve for d
2d-3 = 3(d-3)
2d-3 = 3d - 9
9 - 3 = 3d - 2d
6 = d
Datta is 6 years old
Nancy is 12