Solve c^(x+2)=a^(x-b)

Question

c raised to the power of (x+2) = a raised to the power of (x-b)

Answer 1

c^x+2 = a^x-b

 

log(c^x+2) = log(a^x-b)

 

(x+2)logc = (x-b)loga

 

xlogc + 2logc = xloga - bloga

 

xlogc - xloga = -2logc - bloga

 

x(logc - loga) = -[log(c²) + log(a^b)

 

x = -log(c²a^b) / log(c/a)

 

Answer 2

TRY THIS...

 

c^(x+2)=a(^x-b)

 

(x+2)log c = (x-b) log a

 

(x+2) = (x-b)(log a/log c)

 

(x+2) = (x)(log a/log c) - (b)(log a/log c)

 

x - (x)(log a/log c) = -2 - (b)(log a/log c)

 

(x)(1 - log a/log c) = -2 - (b)(log a/log c)

 

x = [-2 - (b)(log a/log c)]/(1 - log a/log c)