a, b, c are real number then what is the minimum value of the equation ((a+1)^2/a)+((b+1)^2/b)+((c+1)^2/c)=?

Question

Find out minimum value of the equation 

Answer 1

(a+1)²/a+(b+1)²/b+(c+1)²/c=6+(a+1/a)+(b+1/b)+(c+1/c)

The minimum value is reached when a=b=c=-1, This is local minimum.

Min[(a+1)²/a+(b+1)²/b+(c+1)²/c]=0. This is a lo

(When a, b, and c approach zero from left, then the value of the expression goes to -∞ But this is asymptotic value)