Phillip R. answered 08/28/14
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the assumption is at most 2 points lie on a unique line. In other words, we can not draw a straight line through 3 points or 4 points. So draw points A, B, C, and D at the corners of a square for example.
Starting with A draw a line segment to each of the other points. There are 3.
Now starting with B do the same and we get 2 line segments because we can't draw one to point A. This is because segment AB is the same as segment BA.
Finally draw a segment between C and D.
There are a total of 6 line segments.
Using the principle of combinations if you have 4 elements and you combine them two at a time and order does not matter, then the number of combinations possible is 4! / 2! 2! = 4*3*2*1 / 2*1*2*1 = 24 / 4 = 6