
Kenneth S. answered 12/11/17
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suppose the total length is L yards.
sketch the two corrals. there are three widths and one overall length (which I designated as 2w) // to the river.
Each area is xw (two equal rectangular corrals).
Perimeter equation (using up all of the available fencing): 3w + 2x = L so x = ½(L - 3w)
area xw, to be maximized, is f(w) = ½w(L - 3w). Remember, L is a constant (6 yd, according to you)
f(x) is a parabola and its vertex is the maximum value. Now can you complete the work?