The width of a rectangle is 5 feet less than its length find the dimensions of the rectangle if its perimeter is 38 ft

Question

I need to know the dimensions of the rectangle if the perimeter is 38 ft

Answer 1

P = 2(W + L)

 

P = 38

 

W = L - 5

 

38 = 2[(L - 5) + L]

 

38 = 2L - 10 + 2L

 

48 = 4L

 

L = 48/4 = 12

W = L - 5 = 12 - 5 = 7

 

Length:  12 feet

Width:  7 feet