
Suresh R. answered 07/29/14
Tutor
4.9
(344)
All Math, Physical, Computer Sciences and Test Prep.
In the 2 seconds of reaction time, distance traveled = 54km/hr * 2secs = 54000m/3600sec * 2 sec = 30 m
Once he brakes, assuming constant deceleration, Apply Newton's Third Law of Motion:
v^2 - u^2 = 2as
0^2 - 54^2 = 2* -6 * s Final speed is zero on coming to rest.
-2916 = -12s
s = 243 m
Total distance traveled after realizing the need to brake = 30m + 243m = 273m