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A particle move rectilinearly with a constant acceleration of 1m/s2? .its speed after 10second is 5 m/s .The distance cover by particle in this duration is ? (

A particle move rectilinearly with a constant acceleration of 1m/s2 .its speed after 10second is 5 m/s .The distance cover by particle in this duration is ? ( intial and final velocities are in opposite direction )
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1 Answer

If it started from 0 and accelerated at 1 m/s/s for 10 s how fast would it be going?
=> 10 m/s
So it must have started from a negative speed of -5 m/s to get to 5 m/s after 10 sec.
 
Are you sure it is asking for distance and not displacement?
Start at a point, go for 5 sec negative while slowing to 0 m/s,
   then 5 sec positive speeding up to 5 m/s
And you get back to where you started => displacement is zero.
The distance traveled is from the formula xf = x0 + v0t + 1/2(at2)
but you need to do it in 2 parts
SO
x = 1/2(at2) = 1/2(1 m/s/s) (5 s)2
   = 12.5 m in negative direction
them another 12.5 meters coming back
  = 25 meters distance traveled.