Raymond B. answered 07/25/25
Math, microeconomics or criminal justice
A= 1 through 4, B 3 through 6, C 2.3.6.7
8 is outside all 3 overlapping circles, not in A, B or C
1) A'U(B'nC) = 2,5,6,7,8
A' = 5 through 8
B' = 1,2, 7,8
B'nC = 2,7
2) An(BnC') = 4
C' =1,4,5,8
BnC'=4,5
3) A'n(B'UC') = 1,2,4
B'UC' = 1,2,4,5,7,8
4) (AUBUC)' = 8
AUBUC = 1 through 7
AU B = 1 through 6
A intersection B =3 and 4
A U C = 1 through 4 and 6 and 7
A intersection C = 2 and 3
B U C = 3 through 7
B intersection C = 2,3 and 6