Complete the point-slope equation of the line through (-2,6) and (1,1) when y-6=

Question

PLEASE HELP

Answer 1

First you need to find the slope, (y₂-y₁)/(x₂-x₁).  This is (1-6)/(1-(-2)) or -5/3

 

Now that you know the slope you can use that for the point-slope equation

 

The point-slope equation is y-y₁ = m(x-x₁).  If we start with y-6, the x value is -2 (from our point (-2,6)

 

y-6 = -5/3 (x-(-2))

y-6 = -5/3 (x+2)