perpendicular to the line that passes through the points (,-11) and (17,-7), containing the point (19,5)

Question

perpendicular to the line that passes through the points (,-11) and (17,-7), containing the point (19,5)

 

put in slope intercept form

Answer 1

(a,-11) and (17,-7) have a line through them with slope = rise over run = 4/(17-a)

a perpendicular line has negative inverse slope = (a-17)/4

y = (a-17)x/4 + b. to find b plug in the given point (19,5)

5 = (a-17)(19)/4 +b

b = 5 +(17-a)(19)/4

y = (a-17)x/4 + 5 +(17)(19)/4 - 19a/4

y = (a-17)x/4 + 343/4 - 19a/4

or

y = .25(a-17)x + 85.75 - 4.75a