Tina W.

asked • 04/23/17

I have a problem that is supposed to be solved with the elimination method, but I think this problem is unsolvable

my problem is 
 
9x-3y=6
6x-2y=14
 
This is how I tried to solve the problem:
(2)9x-3y=6(2)
(-3)6x-2y=14(-3)
 
 18x- 6y=12
-18x+6y=-42
 
no matter how I try to solve this problem with elimination it eliminates both x and y.
am I missing something or is this problem unsolvable?

Arturo O.

In addition to the answers given by the tutors, note that the principal determinant of the system is zero, which is sufficient to know there is no solution.
 
| 9   -3 |
| 6   -2 |  =  9(-2) - 6(-3) = 0
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04/23/17

Kenneth S.

It is BEST TEACHING PRACTICE to learn that a system of two linear equations may have three possible outcomes in the attempt to solve the system:
 
1. (Normal case) one point, specified by a specific ordered (x,y) pair
2. one line (thus infinitely many solutions--when the two equations are equivalent, e.g. one is a multiple of the other)
3. No points, when the equations represent parallel lines having different y-intercepts, and thus no intersection.
 
0, 1 or infinite # of points!
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04/23/17

3 Answers By Expert Tutors

By:

David W. answered • 04/23/17

Tutor
4.7 (90)

Experienced Prof

Andrew M. answered • 04/23/17

Tutor
New to Wyzant

Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

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