
Vicky Y. answered 05/13/16
Tutor
4.9
(18)
Nice Experienced Tutor
if x > 0:
times x both sides:
x^2 + 45 < 14x
x^2 - 14x + 45 < 0
(x-5)(x-9) < 0
5 < x < 9 -- good for x > 0
if x < 0:
times x both sides:
x^2 + 45 > 14x
x^2 - 14x + 45 > 0
(x-5)(x-9) > 0
x < 5 or x > 9
x^2 + 45 > 14x
x^2 - 14x + 45 > 0
(x-5)(x-9) > 0
x < 5 or x > 9
and x < 0
so x < 0
So 5 < x < 9 or x < 0