Arthur D. answered 12/05/13
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5x-3y=2
6x+7y=13
multiply all terms on both sides of the first equation by 6
multiply all terms on both sides of the second equation by 5
6(5x)-6(3y)=6(2)
30x-18y=12
5(6x)+5(7y)=5(13)
30x+35y=65
30x-18y=12
subtract the second equation from the first
53y=53
y=1
substitute 1 for y in either original equation
5x-3y=2
5x-3(1)=2
5x-3=2
5x=5
x=1
solution:(1,1)