Particular Solution

Question

Find the particular solution to y ' = 4sin(x) given the general solution is y = C - 4cos(x) and the initial condition y(Π/2) =2 . 

-4cos(x)

2 - 4cos(x)

5 - 4cos(x)

-2 - 4cos(x)
 

Answer 1

To find the particular solution, we need to solve for C.

 

when x=π/2 , then y=2

 

 

2 = C - 4cos(π/2)

 

 

Solve for C from this equation.

 

2 = C - 4(0)

 

2 = C

 

 

So the particular solution is            y = 2 - 4cos(x)