The electrostatic force between two charges are located 2 meters apart of 15 N. What will be the force between these charges when they are located 1 meter apart

Question

please help!

Answer 1

Coulomb's Law shows that the force is proportional to the inverse square of the distance: F ∝ 1/d²

For example if the distance doubles then,  F ∝ 1/2² => F = 1/4 , the force will be one fourth as much. Likewise if the distance is halved then,  F ∝ 1/(½)² => F = 4, the force will quadruple.

So if the new distance is ½ of the old distance then the force will be 4 times greater than before: 1/(½)² = 4.

4 x 15N = 60 N