Mark M. answered • 10/04/15

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Obtain a z-score table

http://www.utdallas.edu/dept/abp/zscoretable.pdf

z = (X - μ) / σ

For 130 lb

z = (130 - 136) 33.9

z = -6 / 33.9

z = 0.1769

For this z the percent below is 4.75%

For 171 lb

z = (171 - 136) / 33.9

z = 35 / 33.9

z = 1.032

For this z the percent below is 84.85%

The percent between is 84.85% - 4.75% or 80.10%

Interpolation was not done for z-score of more than 2 decimal places.