Inactive Tutor answered 09/11/15
Tutor
New to Wyzant
P=(-5, -10) Q=(5, 20)
The slope intercept form is y = mx + b
The slope m = (y2-y1)/(x2-x1) = (20-(-10)/(5-(-5)) = 30/10 = 3
Initially we have: y = 3x + b
We need to find b. We know the line passes thru (-5,-10) so
put those values in for x and y and solve for b
-10 = 3(-5) + b
-10 = -15 + b
5 = b
Your line is y = 3x + 5