Bad beat question

Question

We are funding a bad beat pot - at our neighborhood game - with winner (winning and bad beat hands) to be drawn at the end of the year. We had a bad beat hand - winner had 4 nines - and bad beat was nines/jacks full. Then we had another bad beat hand - aces/nines full - and bad beat aces/fours full. Question: Are the winners of the winning/losing hands - the four nines and the nines/jacks full - or does the aces/fours become the new bad beat hand? Thanks!

Answer 1

Hi!

I think Alan makes a good point about the loser to the 4 nines. However, it really depends on what your neighborhood game defines as a bad beat.

I would request further clarification on your phrasing, and here is why: typically, casinos do bad-beat jackpots corresponding to the strength of the hand being beat, not necessarily the strength of the winning hand. So, when you say nines/jacks full, are you referring to (9 9 9 J J) or (J J J 9 9)? Similarly, when you say aces/fours full, do you mean (A A A 4 4) or (4 4 4 A A)? This matters because if you are referring to aces full of fours and nines full of jacks, then actually aces full of fours is a significantly stronger hand that was still cracked.

So it depends. If you can, please provide the actual typed-out hands that are being considered, and I can give you a more concrete answer.

Best,

Simon

Answer 2

I would say the loser to the 4 nines, simply because it is a higher ranking hand than a full house.