The mass of an object is Adding of heat will raise the temperature of the object by What is the specific heat of the object? 1400 J/kg ∙ K 3,500,000 J/kg ∙ K 0.00180 J/kg ∙ K 5.60 J/kg ∙ K

Question

The mass of an object is  Adding  of heat will raise the temperature of the object by  What is the specific heat of the object?

	1400 J/kg ∙ K
	3,500,000 J/kg ∙ K
	0.00180 J/kg ∙ K
	5.60 J/kg ∙ K

Answer 1

Let

m = 250 g = 0.25 kg be the mass of the object,

ΔQ = 14 J be the additional heat,

ΔT = 10°C = 10°K be the rise in temperature,

k (to be found) be the specific heat.

The specific heat, k, is the about of heat needed to increase the temperature

of 1 kg of mass by 1°C (= 1°K)

Therefore

ΔQ = kmΔT

From that

k = ΔQ/mΔT

Substituting actual numbers

k = 14J/(0.25kg×10°C) = 5.6 J/kg∙ K