Inactive Tutor answered 05/28/21
Tutor
New to Wyzant
This is just using the power rule: if f(x) = x^a where a is some number, then f'(x) = ax^(a-1).
Thus, h'(x) = πxπ-1-√2x√2 - 1.
Hope this helped!
Kaye K.
asked 05/28/21Differentiate the function h(x)=x^pi-x^√2
Inactive Tutor answered 05/28/21
This is just using the power rule: if f(x) = x^a where a is some number, then f'(x) = ax^(a-1).
Thus, h'(x) = πxπ-1-√2x√2 - 1.
Hope this helped!
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