introductory and intermediate algebra

Question

two investments totaling $35,000 produce an annual income of $2510 one investment yields 6% a year, while the other yields 8% a year. How much is invested at each rate?

Answer 1

I=.06T+.08(35000-T)

2510=2800-.02T

.02T=290

T=14500 invested at 6%

20500 invested at 8%